Staff Selection Commission Combined Higher Secondary Level Exam
Question : The structural composition of the economy refers to:
Option 1: Contribution of various sectors to the GDP
Option 2: Male-female distribution of the population
Option 3: Private and public sectors classification
Option 4: Rural and urban dis
Correct Answer: Contribution of various sectors to the GDP
Solution : The correct option is the Contribution of various sectors to the GDP.
The structural composition of GDP is the amount that each economic sector contributes to the overall GDP. It describes how economic activity is divided up among the different economic sectors.
Question : Which institution has launched the project E-Shakti for the digitisation of all members of self-help groups in India?
Option 1: Small Industries Development Bank of India
Option 2: The Securities and Exchange Board of India
Option 3: Industrial Finance Corporation of India
Option 4: National Bank for Agriculture and Rural Development
Correct Answer: National Bank for Agriculture and Rural Development
Solution : The correct answer is the National Bank for Agriculture and Rural Development.
Through their pilot project, e-Shakti, the National Bank for Agriculture and Rural Development (NABARD) pioneered the digitization of self-help groups (SHGs) in India. This initiative began with the goal of addressing specific challenges, such as the quality of SHG bookkeeping, and assisting banks in making informed lending choices about the groups.
Question : Directions: After interchanging the given two numbers (not digits) what will be the values of expression (I) and (II) respectively? 6 and 4 l. 10 × 6 – 30 ÷ 4 + 20 II. 8 – 4 × 5 + 6 ÷ 2
Option 1: 12 and –6
Option 2: 20 and 55
Option 3: 55 and –20
Option 4: 10 and –6
Correct Answer: 55 and –20
Solution : Given: l. 10 × 6 – 30 ÷ 4 + 20 II. 8 – 4 × 5 + 6 ÷ 2
Let's solve each equation after interchanging the numbers according to the instructions. On interchanging the numbers 6 and 4 in the first equation, we get – = 10 × 4 – 30 ÷ 6 + 20 = 10 × 4 – 5 + 20 = 40 – 5 + 20 = 55 On interchanging the numbers 6 and 4 in the second equation, we get – = 8 – 6 × 5 + 4 ÷ 2 = 8 – 6 × 5 + 2 = 8 – 30 + 2 = –20
Therefore, after solving the given equations the required answer is 55 and –20. Hence, the third option is correct.
Question : In $\triangle$PQR, the angle bisector of $\angle$P intersects QR at M. If PQ = PR, then what is the value of $\angle$PMQ?
Option 1: 75°
Option 2: 80°
Option 3: 70°
Option 4: 90°
Correct Answer: 90°
Solution : In $\triangle$PQR, PQ = PR ⇒ $\angle$Q = $\angle$R = b PM is the angle bisector of $\angle$P. $\angle$QPM = $\angle$RPM = a Apply angle sum property in $\triangle$PQR, ⇒ $\angle$P + $\angle$Q + $\angle$R = 180° ⇒ $\angle$P + b + b = 180° ⇒ $\angle$P = 180° – 2b $\angle$QPM = $\frac{180° – 2b}{2}$ = 90° – b In $\triangle$PQM, Let $\angle$PMQ = $\theta$ ⇒ $\angle$QPM + $\angle$Q + $\angle$M = 180° ⇒ 90° – b + b + $\theta$ = 180° ⇒ $\theta$ = 90° Hence, the correct answer is 90°.
Question : A class is divided into two sections, with 20 students in one section and 30 students in the other. The pass percentages for these sections are 80% and 60%, respectively. What is the pass percentage for the entire class?
Option 1: 60%
Option 2: 68%
Option 3: 70%
Option 4: 78%
Correct Answer: 68%
Solution : The number of students who passed = 80% of 20 + 60% of 30 = $\frac{80 × 20}{100}$ + $\frac{60 × 30}{100}$ = 16 + 18 = 34 Now, the pass percentage of the entire class = $\frac{\text{Number of students passed}}{\text{Total students}}$ × 100 = $\frac{34}{(20 + 30)}$ × 100 = 68% Hence, the correct answer is 68%.
Question : Directions: In the following question, select the odd one from the given alternatives.
Option 1: AG
Option 2: CE
Option 3: BF
Option 4: GF
Correct Answer: GF
Solution : Let's check the options – First option: AG; A→1, G→7, A + G = 1 + 7 = 8 Second option: CE; C→3, E→5, C + E = 3 + 5 = 8 Third option: BF; B→2, F→6, B + F = 2 + 6 = 8 Fourth option: GF; G→7, F→6, G + F = 7 + 6 = 13
The fourth option does not follow the pattern of the other options. Hence, the fourth option is correct.
Question : Air is said to be saturated when -
Option 1: It contains the maximum content of water vapour.
Option 2: Its pressure is minimum.
Option 3: Its thickness is maximum.
Option 4: It blows over the barren land.
Correct Answer: It contains the maximum content of water vapour.
Solution : The correct option is It contains the maximum content of water vapour.
Nitrogen makes up 78% of the gas in the air, oxygen 21%, followed by argon and carbon dioxide in trace amounts. Water vapour is present in the air in varying amounts, along with dust particles. At a specific pressure and temperature, the air is considered to be saturated when it contains the maximum amount of water vapour. It is found that the relative humidity is 100% in such a condition.
Question : Directions: Select the option figure in which the given figure is embedded. (rotation is NOT allowed)
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : Since the rotation is restricted. So, the embedded figure will have the same orientation as the main figure. By comparison of all the option figures, the given question figure is embedded only in the third option figure.
Hence, the third option is correct.
Question : Directions: If the 20th of March 2001 is Tuesday, then what will be the day of the week on the 23rd of April 2021?
Option 1: Friday
Option 2: Tuesday
Option 3: Monday
Option 4: Wednesday
Correct Answer: Friday
Solution : Given: The 20th of March 2001 is Tuesday.
Number of days from 21st of March 2001 to 20th of March 2021 – 365 × 20 = 7300; add 5 days for leap years (2004, 2008, 2012, 2016, and 2020) = 7300 + 5 = 7305 Number of days from 21st of March 2021 to 23rd of April 2021 – March = 11; April = 23 Total number of days: 7305 + 11 + 23 = 7339 The remainder after dividing 7339 by 7 is 3. Tuesday + 3 days = Friday
So, the 23rd of April 2021 will be Friday. Hence, the first option is correct.
Question : The below bar graph shows the number of toys sold by five different shops (i.e., A, B, C, D, and E) in the first week and second week. Find the ratio of the total number of toys sold by shops A, B, and C in the first week to the number of toys sold by shops C, D, and E in the second week.
Option 1: 1 : 13
Option 2: 9 : 1
Option 3: 13 : 9
Option 4: 9 : 13
Correct Answer: 9 : 13
Solution : Total number of toys sold by shops A, B, and C in the first week = 20 + 40 + 30 = 90 Total number of toys sold by shops C, D, and E in the second week = 20 + 60 + 50 = 130 Ratio = 90 : 130 = 9 : 13 Hence, the correct answer is 9 : 13.
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile