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Staff Selection Commission Combined Higher Secondary Level Exam

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Question : What is the value of $\frac{\frac{5}{6} \text { of } \frac{1}{3} \times \frac{12}{25}-\frac{1}{3} \text { of } \frac{5}{6} \times \frac{18}{25}}{\frac{25}{12} \text { of } \frac{1}{6} \times \frac{2}{5}+\frac{3}{8} \text { of } \frac{12}{25} \times \frac{5}{6}}$?

Option 1: $-\frac{3}{13}$

Option 2: $-\frac{5}{13}$

Option 3: $-\frac{8}{25}$

Option 4: $-\frac{3}{25}$

Team Careers360 24th Jan, 2024

Correct Answer: $-\frac{3}{13}$


Solution : Given: $\frac{\frac{5}{6} \text { of } \frac{1}{3} \times \frac{12}{25}-\frac{1}{3} \text { of } \frac{5}{6} \times \frac{18}{25}}{\frac{25}{12} \text { of } \frac{1}{6} \times \frac{2}{5}+\frac{3}{8} \text { of } \frac{12}{25} \times \frac{5}{6}}$
$=\frac{\frac{5}{18}\times \frac{12}{25}- \frac{5}{18} \times \frac{18}{25}}{\frac{25}{72} \times \frac{2}{5}+\frac{9}{50} \times \frac{5}{6}}$
$=\frac{\frac{2}{15}-\frac{1}{5}}{\frac{5}{36}+\frac{3}{20}}$
$=\frac{\frac{2-3}{15}}{\frac{25+27}{180}}$
$=\frac{-1}{15}\times \frac{180}{52}$
$=-\frac{3}{13}$
Hence,

14 Views

Question : Directions: In the following question, out of the four alternatives, select the alternative that will improve the bracketed part of the sentence. In case no improvement is needed, select "No Improvement". 

Einstein was one (of the wisest men) that ever lived.

(1) of the wisest man

(2) wise man

(3) wisest man

(4) No Improvement

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 24th Jan, 2024

Correct Answer: (4)


Solution : The fourth option is the correct choice.

Explanation: In this case, the original sentence is already correct. The use of the superlative "wisest" correctly compares Einstein to a group of individuals, and "men" is the appropriate plural form in this context, as it is

16 Views

Question : The sum of all internal angles of a regular polygon whose one external angle is $20^\circ$ is:

Option 1: $6400^\circ$

Option 2: $3200^\circ$

Option 3: $2880^\circ$

Option 4: $1440^\circ$

Team Careers360 23rd Jan, 2024

Correct Answer: $2880^\circ$


Solution : The number of sides $(n)$ in a regular polygon,
$⇒n = \frac{360^\circ}{E}$
where $E$ is the external angle.
Substituting $E = 20^\circ$ into the equation.
$⇒n = \frac{360^\circ}{20^\circ} = 18$
The polygon has 18 sides.
The sum $(S)$ of all internal angles of a polygon,

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Question : Directions: In the following question, select the one that is different from the other three alternatives.

Option 1: SRT

Option 2: PON

Option 3: KJL

Option 4: VUW

Team Careers360 25th Jan, 2024

Correct Answer: PON


Solution : Let's check the given options –
First option: SRT; S – 1 = R; R + 2 = T
Second option: PON; P – 1 = O; O – 1 = N
Third option: KJL; K – 1 = J; J + 2 = L

7 Views

Question : Directions: In the following question, select the one that is different from the other three alternatives.

Option 1: 3 – 9

Option 2: 5 – 25

Option 3: 7 – 49

Option 4: 8 – 64

Team Careers360 24th Jan, 2024

Correct Answer: 8 – 64


Solution : Let's check the options –
First option: 3 – 9; 9 is a perfect square of 3.
Second option: 5 – 25; 25 is a perfect square of 5.
Third option: 7 – 49; 49 is a perfect square of 7.
Fourth option: 

21 Views

Question : 360 cm2 and 250 cm2 are the areas of the two similar triangles. If the length of one of the sides of the first triangle is 8 cm, then the length of the corresponding side of the second triangle is:

Option 1: $6\frac{1}{5}\;\operatorname{ cm}$

Option 2: $6\frac{1}{3}\;\operatorname{ cm}$

Option 3: $6\frac{2}{3}\;\operatorname{ cm}$

Option 4: $6\;\operatorname{ cm}$

Team Careers360 23rd Jan, 2024

Correct Answer: $6\frac{2}{3}\;\operatorname{ cm}$


Solution : Thales theorem states that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
Let the length of the corresponding side of the second triangle as $x$.
$⇒\mathrm{\frac{Area_1}{Area_2} = \left(\frac{Side_1}{Side_2}\right)^2}$
$⇒\frac{360}{250} = \left(\frac{8}{x}\right)^2$

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