Staff Selection Commission Combined Graduate Level Exam
Question : In the given figure, if KI = IT and EK = ET, then $\angle$ TEI =________.
Option 1: 75°
Option 2: 125°
Option 3: 105°
Option 4: 150°
Correct Answer: 105°
Solution : KI = IT and EK = ET $\angle$ KET = 150° In $\triangle$ KEI and $\triangle$ TEI, KI = IT [Given] EK = ET [Given] EI = EI [Common] So, $\triangle$ KEI $\cong$ $\triangle$ TEI, ⇒ $\angle$ KEI = $\angle$ TEI Now, $\angle$ KET + $\angle$ KEI + $\angle$ TEI = 360° ⇒ 150° + 2 × $\angle$ TEI = 360° ⇒ 2 $\angle$ TEI = 210° ⇒ $\angle$ TEI = 105° Hence, the correct answer is 105°.
Question : Directions: In a code language, SLAIN is written as PKCNU and DENT is written as VPGF. How will CUBOID be written in that language?
Option 1: FKQDWE
Option 2: FJQDWE
Option 3: FKQDVF
Option 4: EWDPKE
Correct Answer: FKQDWE
Solution : Given: SLAIN is written as PKCNU and DENT is written as VPGF.
Follow the pattern to obtain the required code – Thus, SLAIN is coded as PKCNU. And, DENT is written as VPGF. Thus, DENT is coded as VPGF. Similarly, follow the same pattern for CUBOID –
So, CUBOID is coded as FKQDWE. Hence, the first option is correct.
Question : Select the option that can be used as a one-word substitute for the given group of words. A shortened version of a larger work
Option 1: Summary
Option 2: Precise
Option 3: Shorts
Option 4: Abridgement
Correct Answer: Abridgement
Solution : The correct choice is the fourth option.
Abridgement is a term used to describe a version of a larger work that has been condensed. This involves shortening the original work by omitting details while still preserving the essential content and narrative.
The meanings of the other options are as follows:
Question : The sides of a triangle are in the ratio $\frac{1}{2}:\frac{1}{3}:\frac{1}{4}$ and its perimeter is 104 cm. The length of the longest side (in cm) is:
Option 1: 52
Option 2: 48
Option 3: 32
Option 4: 26
Correct Answer: 48
Solution : Given: The ratio of the triangle's sides $=\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$. $=\frac{1}{2} × 12 : \frac{1}{3} × 12 : \frac{1}{4} × 12$ $=6: 4: 3$ The perimeter of the triangle is $104$ cm. $\therefore$ The longest length of the triangle = $\frac{104}{6+4+3}×6= 48$ cm Hence, the correct answer is 48.
Question : Comprehension: In the following passage, some words have been deleted. Fill in the blanks with the help of the alternatives given. Select the most appropriate option for each number.
A marketplace is always abuzz with activity. It is especially (1)___________a visit in the evenings. A (2)_________range of items are on display. (3) _________and getting a satisfactory (4) _________give the necessary sense of (5) __________to the bored housewife and bring a smile (6) ___________her face. People from all (7) __________of life, rich and poor, (8) ___________shoulders with each other. From their busy (9). ___________, here people find time to (10) __________a greeting with friends or neighbours.
Question: Select the most appropriate option to fill in the blank number 10.
Option 1: displace
Option 2: transfer
Option 3: exchange
Option 4: return
Correct Answer: exchange
Solution : The correct choice is the third option.
The word exchange is appropriate in this context as it implies a mutual or reciprocal action of giving and receiving greetings.
People at the marketplace take time from their busy schedules not just to offer greetings but also to receive greetings from friends or neighbours, creating a sense of interaction and connection.
Therefore, the use of exchange in this sentence conveys the idea of a two-way communication of greetings between individuals in the social setting of the marketplace.
Question : If $\sec \theta+\tan \theta=5, (\theta \neq 0)$, then $\sec \theta$ is equal to:
Option 1: $\left(5+\frac{1}{5}\right)$
Option 2: $\frac{1}{2}\left(3+\frac{1}{3}\right)$
Option 3: $\frac{1}{2}\left(5+\frac{1}{5}\right)$
Option 4: $\left(3+\frac{1}{3}\right)$
Correct Answer: $\frac{1}{2}\left(5+\frac{1}{5}\right)$
Solution : Given: $\sec \theta+\tan \theta=5$ ..... equation1 $\sec^{2}\theta - \tan^{2}\theta =1$ ⇒ $(\sec \theta+\tan \theta)(\sec \theta-\tan \theta)=1$ ⇒ $\sec \theta-\tan \theta=\frac{1}{5}$......equation2 Adding equation1 and equation2 $2\sec\theta = 5 + \frac{1}{5}$ ⇒ $\sec\theta=\frac{1}{2}\left(5+\frac{1}{5}\right)$ Hence, the correct answer is $\frac{1}{2}\left(5+\frac{1}{5}\right)$.
Question : The following sentence has been split into four segments. Identify the segment that contains a grammatical error. I am sure that / the postman would be / coming shortly / to deliver the letter.
Option 1: I am sure that
Option 2: coming shortly
Option 3: to deliver the letter
Option 4: the postman would be
Correct Answer: the postman would be
Solution : The fourth option contains the error.
Would is used to express a past event and is the past tense of will, which is used to predict a future event. Since we are talking about a future event, we should use will instead of would.
Therefore, the correct sentence is: "I am sure that the postman will be coming shortly to deliver the letter."
Question : Ankita sold her watch at a 5% loss. If she had sold it for Rs. 300 more, she would have gained 5%. Find the selling price of the watch.
Option 1: Rs. 2,900
Option 2: Rs. 2,750
Option 3: Rs. 3,000
Option 4: Rs. 2,850
Correct Answer: Rs. 2,850
Solution : Ankita sold her watch at a 5% loss. Here, SP = Selling price and CP = Cost price Let the SP of the watch be $x$. Then, CP $= \frac{100}{(100 - \text{Loss}\%)} \times SP =\frac{100}{(100- 5)} \times x = \frac{100}{95}x$ If she sold for 300 more, then $SP = 300 + x$ Then, gain = 5% $CP =\frac{100}{(100 + P)} \times SP = \frac{100}{(100 +5)} \times (x + 300)$ = $\frac{100}{105}(300 + x)$ According to the question, $\frac{100}{105}(300 + x) = \frac{100}{95}x$ $⇒\frac{(300 + x)}{x} = \frac{105}{95}$ $⇒95 \times (300 + x) = 105x$ $⇒28500 + 95x = 105x$ $⇒10x = 28500$ $\therefore x = 2850$ Hence, the correct answer is Rs. 2,850.
Question : Which of the following is not correct about Mahatma Gandhi ?
Option 1: Gandhi advocated complete sepration of Politics from religion.
Option 2: Gandhi believed in non-violence
Option 3: Gandhi believed in the sanctity of means.
Option 4: Gandhi supported close relation between religion and politics.
Correct Answer: Gandhi advocated complete sepration of Politics from religion.
Solution : Correct Answer is Gandhi advocated complete sepration of Politics from religion.
He argued for a religion-based form of secularism, based on the principle of tolerance and plurality as a means of promoting the peaceful co-habitation of various religious communities in India. He did not call for a complete separation of religion from politics. Instead, he used a new form of mass agitation that emphasized truth, tolerance and non-violence, as well as peaceful protests.
Question : Which of the following will yield a maximum discount on INR 7,500? 1. Two successive discounts of 5% and 5% 2. Single discount of 10% 3. Two successive discounts of 8% and 2%
Option 1: 2
Option 2: 1
Option 3: All will yield the same discount
Option 4: 3
Correct Answer: 2
Solution : Amount = INR 7500 1. Two successive discounts of 5% and 5% Net discount % = $5 +5- \frac{5×5}{100}$ = $9.75$ 2. Single discount of 10% 3. Two successive discounts of 8% and 2% Net discount % = $8 +2- \frac{8×2}{100}$ = $9.84$ So, the maximum discount is from option 2, which is a single discount of 10%. Hence, the correct answer is 2.
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